Question

Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.58. How many customers should the company survey in order to be 99% confident that the margin of error is 0.19 for the confidence interval of true proportion of customers who click on ads on their smartphones?

(Round up your answer to nearest whole number)

Answer 1

We have given,

Preliminary estimate for proportion (Known) = 0.58
Margin of error =E=0.19
Level of significance =   0.01
Z critical value is (by using Z table) =2.576
Sample size formula is                   


=44.78