The following table summarizes the results of a study on SAT prep courses, comparing SAT scores of students in a private preparation class, a high school preparation class, and no preparation class. Use the information from the table to answer the questions.
Treatment | # of observations | Sample Mean | Sum of Squares (SS) |
private prep | 60 | 680 | 265,500 |
high school prep | 60 | 650 | 276,120 |
no prep | 60 | 635 | 302,670 |
Using the data provided, calculate the values needed for the ANOVA summary table. (Hint: T, the treatment total, can be calculated as the sample mean times the number of observations. G, the grand total, can be calculated from the values of T once you have calculated them.)
Source | Sum of Squares (SS) | df | Mean Squares (MS) |
between treatments | |||
within treatments |
The sum of squares between treatments is [ Select ] ["61,000", "62,000", "63,000", "64,000"]
The sum of squares within treatments is [ Select ] ["764,230", "846,280", "798,560", "844,290"]
The df between treatments is [ Select ] ["1", "2", "3", "4"]
The df within treatments is [ Select ] ["177", "178", "180"]
The mean square between treatments is [ Select ] ["29,690", "30,400", "31,500", "34,700"]
The mean square within treatments is [ Select ] ["4,150", "5,530", "4,770", "5,900"]
##Answers:
ANOVA table is attached above
1) sum of squares between treatments is 63000
2)the sum of squares within treatments is844290
3)the df between treatments is 2
4) the df within treatments is 177
5) the mean square between treatments is 31500
6) the mean square within treatments is 4770
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