Question

The following table summarizes the results of a study on SAT prep courses, comparing SAT scores...

The following table summarizes the results of a study on SAT prep courses, comparing SAT scores of students in a private preparation class, a high school preparation class, and no preparation class. Use the information from the table to answer the questions.

Treatment # of observations Sample Mean Sum of Squares (SS)
private prep 60 680 265,500
high school prep 60 650 276,120
no prep 60 635 302,670

Using the data provided, calculate the values needed for the ANOVA summary table. (Hint: T, the treatment total, can be calculated as the sample mean times the number of observations. G, the grand total, can be calculated from the values of T once you have calculated them.)

Source Sum of Squares (SS) df Mean Squares (MS)
between treatments
within treatments

The sum of squares between treatments is                            [ Select ]                       ["61,000", "62,000", "63,000", "64,000"]      

The sum of squares within treatments is                            [ Select ]                       ["764,230", "846,280", "798,560", "844,290"]      

The df between treatments is                            [ Select ]                       ["1", "2", "3", "4"]      

The df within treatments is                            [ Select ]                       ["177", "178", "180"]      

The mean square between treatments is                            [ Select ]                       ["29,690", "30,400", "31,500", "34,700"]      

The mean square within treatments is                            [ Select ]                       ["4,150", "5,530", "4,770", "5,900"]      

Homework Answers

Answer #1

##Answers:

ANOVA table is attached above

1) sum of squares between treatments is 63000

2)the sum of squares within treatments is​​​844290

3)the df between treatments is 2

4) the df within treatments is 177

5) the mean square between treatments is​​​​​ 31500

6) the mean square within treatments is 4770

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