Question

A random sample of size n_{1} = 25, taken from a normal
population with a standard deviation σ_{1} = 5.2, has a
sample mean = 85. A second random sample of size n_{2} =
36, taken from a different normal population with a standard
deviation σ_{2} = 3.4, has a sample mean = 83. Test the
claim that both means are equal at a 5% significance level. Find
P-value.

Answer #1

since p value >0.05

we fail to reject null hypothesis | ||

we do not have have sufficient evidence to conclude that means are different |

Given the information below that includes the sample size (n1
and n2) for each sample, the mean for each sample (x1 and x2) and
the estimated population standard deviations for each case( σ1 and
σ2), enter the p-value to test the following hypothesis at the 1%
significance level :
Ho : µ1 = µ2
Ha : µ1 > µ2
Sample 1
Sample 2
n1 = 10
n2 = 15
x1 = 115
x2 = 113
σ1 = 4.9
σ2 =...

A random sample of
n1 = 49
measurements from a population with population standard
deviation
σ1 = 5
had a sample mean of
x1 = 11.
An independent random sample of
n2 = 64
measurements from a second population with population standard
deviation
σ2 = 6
had a sample mean of
x2 = 14.
Test the claim that the population means are different. Use
level of significance 0.01.
(a) Check Requirements: What distribution does the sample test
statistic follow? Explain....

A random sample of
n1 = 49
measurements from a population with population standard
deviation
σ1 = 5
had a sample mean of
x1 = 8.
An independent random sample of
n2 = 64
measurements from a second population with population standard
deviation
σ2 = 6
had a sample mean of
x2 = 11.
Test the claim that the population means are different. Use
level of significance 0.01.(a) Check Requirements: What
distribution does the sample test statistic follow? Explain.
The...

A random sample of
n1 = 49
measurements from a population with population standard
deviation
σ1 = 3
had a sample mean of
x1 = 13.
An independent random sample of
n2 = 64
measurements from a second population with population standard
deviation
σ2 = 4
had a sample mean of
x2 = 15.
Test the claim that the population means are different. Use
level of significance 0.01.
(a) Check Requirements: What distribution does the sample test
statistic follow? Explain....

a simple random sample of size 36 is taken from a normal
population with mean 20 and standard deivation of 15. What is the
probability the sample,neab,xbar based on these 36 observations
will be within 4 units of the population mean. round to the
hundreths placee

a simple random sample of size 36 is taken from a normal
population with mean 20 and standard deivation of 15. What is the
probability the sample,neab,xbar based on these 36 observations
will be within 4 units of the population mean. round to the
hundreths place

A random sample of 49 measurements from a population with
population standard deviation σ1 = 5 had a
sample mean of x1 = 9. An independent random
sample of 64 measurements from a second population with population
standard deviation σ2 = 6 had a sample mean of
x2 = 12. Test the claim that the population
means are different. Use level of significance 0.01.
(a) Compute the corresponding sample distribution value. (Test
the difference μ1 − μ2. Round your answer...

Xbar in the first sample: 0.6
Standard Deviation in the first sample: 1.2
Size of the first sample (n1): 13
Xbar in the second sample: 5.2
Standard Deviation in the second sample: 3.0
Size of the second sample (n2): 17
Use the conservative t-test to test the null hypothesis of
equality of means. Submit the p-value of your test of
significance.

A random sample of size 15 is taken from a normally distributed
population revealed a sample mean of 75 and a standard deviation of
5. The upper limit of a 95% confidence interval for the population
mean would equal?

A random sample of size 36 is taken from a population with mean
µ = 17 and standard deviation σ = 4. The probability that the
sample mean is greater than 18 is ________.
a. 0.8413
b. 0.0668
c. 0.1587
d. 0.9332

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