a) probability that Mark's first absent during the month occurs on or before the month's 5th work day =1-P(not absent in first 5 days)=1-(1-0.1)5 =0.40951
b)
probability that daniel's second absence will happen on or after the 13th workday of his employment =P(at most 1 absence in first 12 days) =P(X=0)+P(X=1)
=(12C0)*(0.12)0(0.88)12+(12C1)*(0.12)1(0.88)11=0.5686
c)
probability that they both are simultaneously absent =0.1*0.3 =0.03
probability that both are simultaneously absent in exactly one day in a 20 work-day month
=(20C1)*(0.03)1(0.97)19 =0.3364
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