A service station owner believes that an equal number of customers prefer to buy gasoline on every day of the week. A manager claims that the number of customers varies by day. Test the manager’s claim using α=0.10. The owner surveyed 739 customers over a period of time. Here are the results: Mon Tue Wed Thu Fri Sat Sun Customers 103 103 125 103 110 95 96 (Hint: 7 days
( here sum of customer day wise is coming 735 please check and revert)
here null hypothesis:Ho:equal number of customers prefer to buy gasoline on every day of the week
alternate hypothesis: Ha: not all days equal number of customers prefer to buy gasoline.
degree of freedom =categories-1 =7-1=6
for 6df and 0.1 level rejection region : 2 >10.645
applying chi square goodness of fit test:
observed | Expected | Chi square | |||
category | Probability(p) | Oi | Ei=total*p | R2i=(Oi-Ei)2/Ei | |
mon | 1/7 | 103.000 | 105.000 | 0.038 | |
tue | 1/7 | 103.000 | 105.000 | 0.038 | |
wed | 1/7 | 125.000 | 105.000 | 3.810 | |
thu | 1/7 | 103.000 | 105.000 | 0.038 | |
fri | 1/7 | 110.000 | 105.000 | 0.238 | |
sat | 1/7 | 95.000 | 105.000 | 0.952 | |
sun | 1/7 | 96.000 | 105.000 | 0.771 | |
total | 1.000 | 735 | 735 | 5.886 |
here as test statistic 5.886 is less than critical value we fail to reject null hypothesis
we do not have evidence to conclude that number of customers prefer to buy gasoline on every day are different
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