When 385 junior college students were surveyed, 185 said they have a passport. Construct a 95% confidence interval for the proportion of junior college students that have a passport. Round to the nearest thousandth. Interpret your answer in terms of the application.
Solution :
Given that,
n = 385
x = 185
Point estimate = sample proportion = = x / n = 185/385=0.481
1 - = 1- 0.481 =0.519
At 95% confidence level
= 1 - 95% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 1.96 ( Using z table )
Margin of error = E = Z/2 * ((( * (1 - )) / n)
= 1.96 (((0.481*0.519) /385 )
= 0.050
A 95% confidence interval for population proportion p is ,
- E < p < + E
0.481-0.050 < p < 0.481+0.050
0.431< p < 0.531
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