Question

Based on historical data, your manager believes that 32% of the company's orders come from first-time customers. A random sample of 178 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is less than 0.29?

Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations.

Answer =  (Enter your answer as a number accurate to 4 decimal places.)

Answer 1

Solution

Given that,

=  [p ( 1 - p ) / n] =   [(0.32 * 0.68) / 178] = 0.0350

P( < 0.29) =

= P[( - ) / < (0.29 - 0.32) / 0.0350]

= P(z < -0.8571)

= 0.1957

Probability= 0.1957