Question

Ho: The amount of people seen at the movies does not vary by the day of the week.

Ha: The amount of people seen at the movies does vary by the day of the week.

The formula to determine the chi-square goodness of fit is: Description: chi square formula chisquare = sum (O-E)^2 / E My chi-square calculation results were 3.995. The p value is .4067. The chi-square critical value at 0.05 is 9.488. Looking back at the null and alternative hypothesis, I see that we fail to reject the null hypothesis. Does that mean we are 95% confident that the evidence does not support the belief that the amount of people seen at the movies does not vary by the day of the week?

Answer 1

Given that the p value is 0.4067, which is greater than the 0.05 significance level. This means that the result is not significant.

Therefore, we cannot reject the null hypothesis. We failed to reject the null hypothesis, this means that the evidence are supporting the null hypothesis statement  

So, your statement is incorrect because when we failed to reject the null hypothesis then we can never conclude that with 95% confidence, there is insufficient evidence to support the null hypothesis statement

Since the null hypothesis is not rejected, so we can say that we are 95% confident that there is sufficient evidence to support the null hypothesis statement