Question

The Roman Arches is an Italian restaurant. The manager wants
to estimate the average amount a customer spends on lunch, Monday
through Friday. A random sample of 100 customers' lunch tabs gave a
mean of $8.75 and a population standard deviation of $2.04.

Construct a 90% confidence interval for the average amount
spent on lunch by all customers.

Answer #1

Jordan is the manager of a used book store. He wants to estimate
the average amount a customer spends per visit. A random sample of
80 customer receipts showed a mean of $6.87 with a standard
deviation of $2.49. Find a 95% confidence interval for the
average amount spent by all of his customers. Include the
interpretation of the interval.
A) Confidence Interval: ( nothing , nothing ) (round each
interval limit to two decimal places)
B) In the...

A random sample of 49 lunch customers was selected at a
restaurant. The average amount of time the customers in the sample
stayed in the restaurant was 40 minutes. From past experience, it
is known that the population standard deviation equals 10
minutes.
a.
Compute the standard error of the mean.
b.
Construct a 95% confidence interval for the true
average amount of time customers spent in the restaurant.
c.
With a .95 probability, what sample size would have to...

(solve manually) a randomn sample of 49 lunch customers was
taken at a restaurant. The average amount of time the customers in
the sample stayed in the restaurant was 45 minutes with a standard
deviation of 14 minutes.
a) Construct a 95% confidence interval for the true average
amount of time customers spent in the restaurant.
b) with a .95 probability, how large of a sample would have to
be taken to provide a margin of error of 2.5 minutes...

A department store manager wants to estimate with a 99%
confidence interval the mean amount spent by all customers at the
store. How large of a sample should be taken if the manager is
willing to tolerate an error of $3. Assume the population standard
deviation is $31.

The table below contains the amount that a sample of nine
customers spent for lunch ($) at a fast-food restaurant. Complete
parts a and b below. 4.33 5.14 5.67 6.31 7.36 7.67 8.48 8.79
9.18
a. Construct a 99% confidence interval estimate for the
population mean amount spent for lunch at a fast-food restaurant,
assuming a normal distribution. The % confidence interval estimate
is from $ nothing to $ nothing. (Round to two decimal places as
needed.)
b. Interpret the...

The table below contains the amount that a sample of nine
customers spent for lunch ($) at a fast-food restaurant. Complete
parts a and b below.
4.87 5.08 5.84 6.14 7.32 7.58 8.22 8.67 9.33
a. Construct a 95% confidence interval estimate for the
population mean amount spent for lunch at a fast-food restaurant,
assuming a normal distribution. The % confidence interval estimate
is from $??? to $???. (Round to two decimal places as
needed.)
b. Interpret the interval constructed...

show step by step
Sam and Hannah, own a restaurant in
Edison, New Jersey, and want to study the dining characteristics of
their customers. They decide to focus on two variables: the amount
of money spent by customers and whether customers order dessert.
The results from a sample of 61 customers are as follows:
Amount spent: Sample mean = $45.83, Sample standard deviation =
$6.27
17 out of the randomly selected 61 customers, purchased
dessert.
Construct a 98%...

The manager of a paint supply store wants to estimate the actual
amount of paint contained in 1-gallon cans purchased from a
nationally known manufacturer. The manufacturer's specifications
state that the standard deviation of the amount of paint is equal
to 0.01 gallon. A random sample of 50 cans is selected, and the
sample mean amount of paint per 1-gallon can is 0.996 gallon.
Complete parts (a) through (d). a. Construct a 95% confidence
interval estimate for the population mean...

The manager of a paint supply store wants to estimate the actual
amount of paint contained in 1-gallon cans purchased from a
nationally known manufacturer. The manufacturer's specifications
state that the standard deviation of the amount of paint is equal
to 0.01 gallon. A random sample of 50 cans is selected, and the
sample mean amount of paint per 1-gallon can is 0.996 gallon.
Complete parts (a) through (d).
d. Construct a 90% confidence interval estimate. How does this
change...

Data were collected on the amount spent by customers
for lunch at a major Houston restaurant. These data are contained
in the file named Houston. Based upon past studies the population
standard deviation is known with .
Click on the datafile logo to reference the data.
Round your answers to two decimal places. Use the critical value
with three decimal places.
a. At 99% confidence, what is the margin of
error?
b. Develop a 99% confidence interval estimate
of the mean...

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