1.)
A population of values has a normal distribution with μ=188.6and
σ=18.4 You intend to draw a random sample of size n=193
Find the probability that a single randomly selected value is less
than 188.1.
P(X < 188.1) =
Find the probability that a sample of size n=193 is randomly
selected with a mean less than 188.1.
P(x¯ < 188.1) =
Enter your answers as numbers accurate to 4 decimal places.
2.)
Scores for a common standardized college aptitude test are
normally distributed with a mean of 501 and a standard deviation of
98. Randomly selected men are given a Test Prepartion Course before
taking this test. Assume, for sake of argument, that the test has
no effect.
If 1 of the men is randomly selected, find the probability that his
score is at least 546.2.
P(X > 546.2) = Round to 4 decimal
places.
If 17 of the men are randomly selected, find the probability that
their mean score is at least 546.2.
P(X¯ > 546.2) = Round to 4 decimal places.
If the random sample of 17 men does result in a mean score of
546.2, is there strong evidence to support the claim that the
course is actually effective?
3.)
The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.5 years and a standard deviation of 0.4 years. He then randomly selects records on 54 laptops sold in the past and finds that the mean replacement time is 3.4 years.
Assuming that the laptop replacement times have a mean of 3.5 years and a standard deviation of 0.4 years, find the probability that 54 randomly selected laptops will have a mean replacement time of 3.4 years or less.
P(¯¯X≤3.4 years)P(X¯≤3.4 years) = Round to 4 decimal places.
Based on the result above, does it appear that the computer store
has been given laptops of lower than average quality?
4.)
The amounts of nicotine in a certain brand of cigarette are
normally distributed with a mean of 0.883 g and a standard
deviation of 0.281 g. The company that produces these cigarettes
claims that it has now reduced the amount of nicotine. The
supporting evidence consists of a sample of 32 cigarettes with a
mean nicotine amount of 0.828 g.
Assuming that the given mean and standard deviation have
NOT changed, find the probability of randomly selecting 32
cigarettes with a mean of 0.828 g or less.
P(X¯ < 0.828 g) = Round to 4 decimal places.
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