Question

# In a random sample of 35 refrigerators, the mean repair cost was \$29.00  and the population standard...

In a random sample of 35 refrigerators, the mean repair cost was \$29.00  and the population standard deviation is \$15.90 .

Construct a 95% confidence interval for the population mean repair cost. Interpret the results.

95%  confidence interval is________ ?   (Round to two decimal places as needed.)

A. With 95 % confidence, it can be said that the confidence interval contains the sample
mean repair cost.
B. With 95 % confidence, it can be said that the confidence interval contains the true mean
repair cost.
C. The confidence interval contains 95 % of the mean repair costs.

soln:

b. with 95% confidence ,it can be said that the confidence interval  contains the true mean repair cost

Sol 100(1-o)-95 >a-O05 < 7*+5tp *1* zma m+ Heve, 29,n-35, S-1 90 o0-05 too2534 2.0322 15-90 N35 e[ (29-15.02-0372) AL29+2-03 35 1-o -> P[23.54 34.461-0 cH (23-54,3446) corgadence coeidedt 0-95 co84h.

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