Question

The manufacturer of an over-the-counter heartburn relief medication claims that its product brings relief in less than 3.0 minutes, on average. To be able to make this claim, the manufacturer was required by the FDA to present statistical evidence in support of the claim. The manufacturer reported that for a sample of 100 heartburn sufferers, the mean time to relief was 3.3 minutes and the population standard deviation was 1.1 minutes. What is the probability of obtaining a sample with a mean time to relief of at least 3.3 minutes?

Use Excel or JMP to find probabilities and values. Do not round intermediate calculations. Round your final answer to four decimals. Use number format 0.0000 Do not use probability tables to find probabilities.

Answer 1

Given that the true mean is 3 minutes, the distribution of the sample mean of sample size n = 100 is given as:

The probability now is computed here as:

Converting it to a standard normal variable, we have here:

Getting it in EXCEL, we have:
=1-norm.dist(2.7273,0,1,TRUE)

The output of which is 0.0032

Therefore 0.0032 is the required probability here.

answered by: anonymous