Question

1) Assume that 43% of people are left-handed. If we select 5 people at random, find...

1) Assume that 43% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below, rounded to four decimal places:

a. There are some lefties (≥ 1) among the 5 people.

b. There are exactly 3 lefties in the group.

c. There are at least 4 lefties in the group.

d. There are no more than 2 lefties in the group.

e. How many lefties do you expect?

f. With what standard deviation?

if you just work it out, please show work, but if you use excel to solve it, please tell me what command did you use to solve it?? thank you~

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Assume that 42% of people are left-handed. If we select 5 people at random, find the...
Assume that 42% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below, rounded to four decimal places: a. There are some lefties (≥ 1) among the 5 people. b. There are exactly 3 lefties in the group. c. There are at least 4 lefties in the group. d. There are no more than 2 lefties in the group. e. How many lefties do you expect? f. With what standard deviation?
Assume that 61% of people are left-handed. If we select 5 people at random, find the...
Assume that 61% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below, rounded to four decimal places: a. There are some lefties (≥ 1) among the 5 people. b. There are exactly 3 lefties in the group. c. There are at least 4 lefties in the group. d. There are no more than 2 lefties in the group. e. How many lefties do you expect? f. With what standard deviation?
Assume that 12% of people are left-handed. If we select 5 people at random, find the...
Assume that 12% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below, rounded to four decimal places: a. There are some lefties (≥ 1) among the 5 people. b. There are exactly 3 lefties in the group. c. There are at least 4 lefties in the group. d. There are no more than 2 lefties in the group. e. How many lefties do you expect? f. With what standard deviation?
Assume that 32% of people are left-handed. If we select 5 people at random, find the...
Assume that 32% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below, rounded to four decimal places: a. There are some lefties ( ≥ 1) among the 5 people. b. There are exactly 3 lefties in the group. c. There are at least 4 lefties in the group. d. There are no more than 2 lefties in the group. e. How many lefties do you expect? f. With what standard...
Assume that 64% of people are left-handed. If we select 5 people at random, find the...
Assume that 64% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below, rounded to four decimal places: a. There are some lefties (≥ 1) among the 5 people. b. There are exactly 3 lefties in the group. c. There are at least 4 lefties in the group. d. There are no more than 2 lefties in the group. e. How many lefties do you expect? f. With what standard deviation?
2) Assume that 13% of people are left-handed. If we select 5 people at random, find...
2) Assume that 13% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below. a. The first lefty is the fifth person chosen. b. There are some lefties among the 5 people. c. There are exactly 3 lefties in the group d. There are at least 3 lefties in the group e. There are no more than 3 lefties in the group f. How many lefties do you expect? g. With...
Assume that 13% of people are left-handed. If we select 5 people at random, find the...
Assume that 13% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below. a) The first lefty is the fifth person chosen. b) There are some lefties among the 5 people. c) The first lefty is the second or third person. d) There are exactly 3 lefties in the group. e) There are at least 3 lefties in the group. f) There are no more than 3 lefties in the group.
assume that 11% of people are left handed, if we seclect 5 people at random, find...
assume that 11% of people are left handed, if we seclect 5 people at random, find the probability there are exactly 3 lefties in the group b) there are at least 3 lefties in the group c) there are no more than lefties in the group I have to show the formula used and steps Thank you
Assume that 10% of people are left-handed and selecting 12 people at random is a binomial...
Assume that 10% of people are left-handed and selecting 12 people at random is a binomial experiment. Calculate the following probabilities. a ) There are some lefties in the group b) There are no lefties in the group c) There are exactly 3 lefties in the group d) There are at least 7 lefties in the group e) There are no more than 5 lefties in the group f) More than the average number of lefties
Assume that 13% of people are left handed. If we select 5 people at random, find...
Assume that 13% of people are left handed. If we select 5 people at random, find the probability below: a) the first lefty is the fifth person chosen = .0745 b) the first lefty is the second or third person = .211 How do you solve both problems in R?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT