The following are six observations collected from treatment 1, ten observations collected from treatment 2, and eight observations collected from treatment 3. Test the hypothesis that the treatment means are equal at the 0.05 significance level.
Treatment 1 | Treatment 2 | Treatment 3 |
3 | 9 | 6 |
2 | 6 | 3 |
5 | 5 | 5 |
1 | 6 | 5 |
3 | 8 | 5 |
1 | 5 | 4 |
4 | 1 | |
7 | 5 | |
6 | ||
4 | ||
Find the 95% confidence interval for the difference between treatment 2 and 3. (Round your answers to 2 decimal places.)
critical value of t with 0.05 level and N-k=21 degree of freedom= | tN-k= | 2.080 |
Fisher's (LSD) for group i and j =(tN-k)*(sp*√(1/ni+1/nj) =2.080*sqrt(2.5238*(1/10+1/8))= | 1.57 |
95% confidence interval for the difference between treatment 2 and 3 =estimate difference -/+ LSD
=(6-4.25) -/+ 1.57
=0.18 to 3.32
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