After a repeated observation, it has been determined that the waiting time at the drive through window of a local bank is skewed left, with a mean of 3.5 minutes and a standard deviation of 1.9 minutes. a random sample of 100 customers is to be taken. What is the probability that the mean of the sample will exceed 4 minutes? show the numbers in the calculation. I am not getting the right equation
Given that, mean = 3.5 minutes and standard deviation = 1.9 minutes
sample size ( n ) = 100
Mean and standard deviation of the sampling distribution of sample mean are,
We want to find,
Therefore, the probability that the mean of the sample will exceed 4 minutes is 0.0043
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