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Problem 5: A bus company advertised a mean time of 150 minutes for a trip between...

Problem 5:

A bus company advertised a mean time of 150 minutes for a trip between two cities. A consumer group had reason to believe that the mean time was more than 150 minutes. A sample of 20 trips showed a mean x̄ = 153 minutes and a standard deviation s = 7.5 minutes. At an α = .10 level of significance, test the consumer group’s belief. Assume that trip lengths with this bus company follow a normal distribution. Make sure that any necessary assumptions for conducting the hypothesis test are satisfied.

A) State the null and alternative hypothesis.

H0:

Ha:                                                                                          

B) Determine the critical value(s) for the test.

C) Compute the test statistic (show your work).

D) Make your decision.

E) State your conclusion in terms of the professor’s claim.

                                                           

Homework Answers

Answer #1

a)

H0: = 150

Ha: > 150

b)

Critical value t(α, n-1) = t(0.1 , 20-1) = 1.328

c)

Test Statistic :-
t = ( X̅ - µ ) / (S / √(n) )
t = ( 153 - 150 ) / ( 7.5 / √(20) )
t = 1.79

d)

Test Criteria :-
Reject null hypothesis if t > t(α, n-1)

t > t(α, n-1) = 1.7889 > 1.328
Result :- Reject null hypothesis

e)

We have sufficient evidence to conclude that the true mean time was more than 150 minutes.

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