Question

Problem 5: A bus company advertised a mean time of 150 minutes for a trip between...

Problem 5:

A bus company advertised a mean time of 150 minutes for a trip between two cities. A consumer group had reason to believe that the mean time was more than 150 minutes. A sample of 20 trips showed a mean x̄ = 153 minutes and a standard deviation s = 7.5 minutes. At an α = .10 level of significance, test the consumer group’s belief. Assume that trip lengths with this bus company follow a normal distribution. Make sure that any necessary assumptions for conducting the hypothesis test are satisfied.

A) State the null and alternative hypothesis.

H0:

Ha:                                                                                          

B) Determine the critical value(s) for the test.

C) Compute the test statistic (show your work).

D) Make your decision.

E) State your conclusion in terms of the professor’s claim.

                                                           

Homework Answers

Answer #1

a)

H0: = 150

Ha: > 150

b)

Critical value t(α, n-1) = t(0.1 , 20-1) = 1.328

c)

Test Statistic :-
t = ( X̅ - µ ) / (S / √(n) )
t = ( 153 - 150 ) / ( 7.5 / √(20) )
t = 1.79

d)

Test Criteria :-
Reject null hypothesis if t > t(α, n-1)

t > t(α, n-1) = 1.7889 > 1.328
Result :- Reject null hypothesis

e)

We have sufficient evidence to conclude that the true mean time was more than 150 minutes.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A bus company advertised a mean time of 150 minutes for a trip between two cities....
A bus company advertised a mean time of 150 minutes for a trip between two cities. A consumer group had reason to believe that the mean time was significantly different from 150 minutes. A sample of 40 trips showed a mean x̄= 153 minutes and a standard deviation s=7.5 minutes. At the 4% level of significance, test the advertisement claim. Apply two-sided test, and give all six steps of the procedure clearly. Finally interpret the conclusion in terms of the...
A public bus company official claims that the mean waiting time for bus number 14 during...
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.9 minutes with sample standard deviation s = 1.5 minutes. At the 0.01 significance level, test the claim that the mean waiting time is less than 10 minutes. a) Write the null and alternative hypotheses. b) Determine the P-value. c)...
Suppose that the average trip time from Oak Park to UIC on the Blue line is...
Suppose that the average trip time from Oak Park to UIC on the Blue line is 22 minutes and that the standard deviation of the population is 16 minutes (sigma=16). We are interested to know whether the average trip time on Thursdays is longer. We study a sample of 49 trips on Thursdays and the average is 23.75 minutes. Execute a hypothesis test at alpha=5% that the average trip time on Thursdays is longer (that is, that it requires a...
Four different paints are advertised as having the same drying time. To check the manufacturers' claims,...
Four different paints are advertised as having the same drying time. To check the manufacturers' claims, five samples were tested for each of the paints. The time in minutes until the paint was dry enough for a second coat to be applied was recorded. Conduct an analysis to see whether the mean drying time is the same for each type of paint. Paint 1 Paint 2 Paint 3 Paint 4 128 144 133 150 137 133 132 142 135 138...
In an advertisement, a pizza shop claims its mean delivery time is 30 minutes. A consumer...
In an advertisement, a pizza shop claims its mean delivery time is 30 minutes. A consumer group believes that the mean delivery time is greater than the pizza shop claims. A random sample of 41 delivery times has a mean of 31.5 minutes with standard deviation of 3.5 minutes. Does this indicate at a 5% significance level that the mean delivery time is longer than what the pizza shop claims? Step 1: State the null and alternative hypothesis. Step 2:...
A delivery company claims that the mean time it takes to deliver frozen food between two...
A delivery company claims that the mean time it takes to deliver frozen food between two particular cities is 4 hours. A consumer advocacy group wishes to show at the 5% level that the mean time is greater than 4 hours. A random sample of 50 deliveries yielded a sample mean of 4.2 hours with a standard deviation of 0.5 hours. 1. Set up the null and alternative hypotheses. 2. Compute the test statistic. 3. State the p-value for the...
The population mean waiting time to check out of a supermarket has historically been 4 minutes....
The population mean waiting time to check out of a supermarket has historically been 4 minutes. In an effort to reduce the waiting time, you, as store manager, conducted an experiment with infrared cameras that use body heat and in-store software to determine how many lanes should be opened. To test the effectiveness of this process, you selected a random sample of 100 customers and recorded their waiting time. For this sample, the mean waiting time to check out was...
A new bus route has been established between downtown Denver and Englewood (a suburb of Denver)....
A new bus route has been established between downtown Denver and Englewood (a suburb of Denver). Eric has taken the bus to work for many years. For the old bus route, he knows from long experience that the mean waiting time between buses at his stop was 20 minutes. However, a random sample of 34 waiting times between buses using the new route had a mean of 17.2 minutes with a sample standard deviation of 6.4 minutes. Does this indicate...
Flying time on an old route between 2 cities has a mean value of =5.25 hours...
Flying time on an old route between 2 cities has a mean value of =5.25 hours with standard deviation is =0.6 hours. There are 36 flights on a new route where the mean is hours. Does this indicate that the average flying time for the new route is less than 5.25 hours? Use a 5% level of significance. State the null and alternate hypothesis. Will you use a left tail, right tail or 2 tailed test? Identify the sampling distribution...
Historically, evening long-distance calls from a particular city have averaged 15.2 minutes per call. In a...
Historically, evening long-distance calls from a particular city have averaged 15.2 minutes per call. In a random sample of 35 calls, the sample mean time was 14.3 minutes. Assume the standard deviation is known to be 5 minutes. Using a 0.05 level of significance, is there sufficient evidence to conclude that the average evening long-distance call has decreased? Note: Use the six-steps – clearly labeled (15 pts.) State the null hypothesis and the alternative hypothesis Determine the critical value(s); (draw...