Question

Two signals reach the receiver independently, each in an interval of 0- 2 minutes. Jamming occurs if the time difference between their arrival is less than 0.2 min. What is the probability that jamming will take place?

Answer 1

At first the distribution of 0-2 mins has to be provided here to solve this question but since it is not provided here we can consider the same as uniform distribution.

So the probability = interval width / (b-a)

where b is the upper range b= 2min

a is the lower range a= 0 min

and the range = 0.2 min

So the probability = 0.2/(2-0) = 0.1 or 10%

The image for the uniform distribution is provided below.

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