The probability that a part inspected is defective is 0.09, what is the probability of having 2 defects out of the next 5 parts inspected? Name the distribution. Generate Probability Distr. Function
Let X be the number of defects. Then
with
X | P(X=x) |
0 | 0.6240 |
1 | 0.3086 |
2 | 0.0610 |
3 | 0.0060 |
4 | 0.0003 |
5 | 0.0000 |
We need to find P(X=2)
Let me know in the comments if anything is not clear. I will reply ASAP! Please do upvote if satisfied!
Get Answers For Free
Most questions answered within 1 hours.