Women have head circumferences that are normally distributed with a mean given by u= 23.76in, and a standard deviation given by o= 1.1in.
a. If a hat company produces women's hats so that they fit head circumferences between 23.1 in. and 24.1 in., what is the probability that a randomly selected woman will be able to fit into one of these hats? The probability is . 4165. (Round to four decimal places as needed.)
Sol:
sample mean=xbar=mu=23.76
sample standard deviation=sigma/sqrt(n)=1.1/sqrt(1)=1.1
xbar follows approximately normal distribution with
xbar~N(23.76,1.1)
need to find
P(23.1<xbar<24.1)
need to convert z scores as
z=x-mean/sd
P(23.1-23.76/1.1<Z<24.1-23.76/1.1)
P(-0.6<Z<0.3090909)
P(z<0.3090909)-P(Z<-0.6)
0.6214-0.2743
=0.3471
answer is 0.3471,it cannot be 0.4165.check
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