The results of a mathematics placement exam at two different
campuses of Mercy College follow:
Campus | Sample size | Mean | Population Std. Deviation |
1 | 1,533 | 32 | 19 |
2 | 294 | 29 | 17 |
Is there a difference in the mean score of Campus 1 and Campus 2 of
Mercy College? Given that the two population standard deviations
are known, what is the p-value?
1.0129
0.0066
0.1129
1.0000
Solution:
Given that,
= 32
= 29
= 19
= 11
n1 = 1533
n2 = 294
This is a two tailed test
The null and alternative hypothesis is,
Ho: =
Ha :
The test statistic
z = ( - ) / ( / n1) + ( / n2 )
= ( 32 - 29 ) / ( 192/1533) + ( 112 / 294)
= 2.718
p-value = 2*P(Z > z )
= 2*(1 - P(Z < z ))
= 2*( 1- P(Z < 2.718))
= 2*( 1 - 0.9967)
= 2* 0.0033
= 0.0066
The p-value is 0.0066
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