Question

Suppose the actual proportion of USU students who feel parking is a problem is 0.70. A...

Suppose the actual proportion of USU students who feel parking is a problem is 0.70. A student takes a poll of 100 randomly selected Purdue students and asks them if they feel that parking is a problem.

a. What is the mean for the sample proportion?

b. What is the standard deviation for the sample proportion? (Use 4 decimals)

c. What is the probability that the sample proportion is greater than 0.75? (Use 4 decimals)
  
d. Between what two values does the middle 95% of the sample proportions lie? (Use 4 decimals)

Homework Answers

Answer #1

Given data

population proportion (p) =0.70

number of sample (n)=100

a) mean of the sample proportion

will be same as the sample population proportion

b)Standard deviation for the sample will be

c)now we have to find the probability of that sample proportion is greater than 0.75

So

Now test Statistic


Now from the standard probability distribution table the probability less than Z=1.09 will be

the probability of getting sample proportion greater than 0.75 will be

d) Since this distribution is a normal distribution so According to empirical rule the 95 % of the sample proportion lies within 2 standard deviation of the mean

that is

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A student was asked to find a 90% confidence interval for the proportion of students who...
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 88. Which of the following is a correct interpretation of the interval 0.1 < p < 0.3? Check all that are correct. The proprtion of all students who take notes is between 0.1 and 0.3, 90% of the time. There is a 90% chance that the proportion of notetakers in a sample...
A student was asked to find a 90% confidence interval for the proportion of students who...
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 84. Which of the following is a correct interpretation of the interval 0.1 < p < 0.31? Check all that are correct. With 90% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.1 and 0.31. There is a 90% chance that the proportion of...
A student was asked to find a 90% confidence interval for the proportion of students who...
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 78. Which of the following is a correct interpretation of the interval 0.13 < p < 0.27? Check all that are correct. 0 There is a 90% chance that the proportion of the population is between 0.13 and 0.27. 0 The proprtion of all students who take notes is between 0.13 and...
Suppose it is desired to compare the proportion of male and female students who voted in...
Suppose it is desired to compare the proportion of male and female students who voted in the last presidential election. We decide to randomly and independently sample 1000 male and 1000 female students and ask if they voted or not. A printout of the results is shown below. Hypothesis Test - Two Proportions Sample Size Successes Proportion Males 1000 475 0.47500 Females 1000 525 0.52500 Difference -0.05000 Null Hypothesis: p1 = p2 Alternative Hyp: p1 ≠ p2 SE (difference) 0.02236...
A student at a university wants to determine if the proportion of students that use iPhones...
A student at a university wants to determine if the proportion of students that use iPhones is less than 0.33. The hypotheses for this scenario are as follows. Null Hypothesis: p ≥ 0.33, Alternative Hypothesis: p < 0.33. If the student takes a random sample of students and calculates a p-value of 0.0466 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance. 1) The proportion of students that use iPhones is greater than...
1. A university Dean is interested in determining the proportion of students who receive some sort...
1. A university Dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than examine the records for all students, the dean randomly selects 200 students and finds that 118 of them are receiving financial aid. By hand, and using formulas for the “Margin of Error” (i.e. not calculator confidence interval), find a 98% confidence interval to estimate the true proportion of students on financial aid. (Use 3 decimal places for proportions.) 2....
5. Mean of 1500, standard deviation of 300. Estimating the average SAT score, limit the margin...
5. Mean of 1500, standard deviation of 300. Estimating the average SAT score, limit the margin of error to 95% confidence interval to 25 points, how many students to sample? 6. Population proportion is 43%, would like to be 95% confident that your estimate is within 4.5% of the true population proportion. How large of a sample is required? 7. P(z<1.34) (four decimal places) 8. Candidate only wants a 2.5% margin error at a 97.5% confidence level, what size of...
(Use a calculator for this problem) The combined (verbal + quantitative reasoning) score on the GRE...
(Use a calculator for this problem) The combined (verbal + quantitative reasoning) score on the GRE is normally distributed with mean 1066 and standard deviation 191. (a) What proportion of combined GRE scores can be expected to be under 1100? (b) What proportion of combined GRE scores can be expected to be over 1100? (c) What proportion of combined GRE scores can be expected to be between 950 and 1000? (d) What is the probability that a randomly selected student...
Let's say you want to poll a random sample of 150 students on campus to see...
Let's say you want to poll a random sample of 150 students on campus to see if they prefer to take online classes. Of course, if you took an actual poll you would only get one number (your sample proportion, p-hat). Imagine all the possible samples of 150 students that you could draw and the distribution of all the possible sample proportions you would get from them. If I told you that we know that 35% of all students actually...
In order to estimate the proportion of university students who need a dental treatment, a sample...
In order to estimate the proportion of university students who need a dental treatment, a sample of 25 students selected at random revealed that 150 of them need some dental treatment. Use 95% Confidence level to answer the following: a. What is the point estimate for the population proportion? b. Compute the Standard error of the proportion. c. What is the critical value used for this estimate? d. What is the total error E? e. What is the minimum and...