Question

The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's in-state and out-of-state applicants. A random sample of 9 in-state applicants results in a SAT scoring mean of 1238 with a standard deviation of 49. A random sample of 17 out-of-state applicants results in a SAT scoring mean of 1150 with a standard deviation of 35. Using this data, find the 99% confidence interval for the true mean difference between the scoring mean for in-state applicants and out-of-state applicants. Assume that the population variances are not equal and that the two populations are normally distributed.

Step 2 of 3:

Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.

The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's in-state and out-of-state applicants. A random sample of 9 in-state applicants results in a SAT scoring mean of 1238 with a standard deviation of 49. A random sample of 17 out-of-state applicants results in a SAT scoring mean of 1150 with a standard deviation of 35. Using this data, find the 99% confidence interval for the true mean difference between the scoring mean for in-state applicants and out-of-state applicants. Assume that the population variances are not equal and that the two populations are normally distributed.

Step 3 of 3:

Construct the 99% confidence interval. Round your answers to the nearest whole number.

Answer 1

Margin of error = t*se = 2.994*18.408 = 55.113552