Question

For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. A random sample of 5454 physicians in Colorado showed that 3062 provided at least some charity care (i.e., treated poor people at no cost). (a) Let p represent the proportion of all Colorado physicians who provide some charity care. Find a point estimate for p. (Round your answer to four decimal places.)

Upper Limit:

Lower Limit:

Answer 1

a) Let p represent the proportion of all Colorado physicians who provide some charity care. Find a point estimate for p. (Round your answer to four decimal places.)

p=x/n=3062/5454=0.5614228=0.5614

point estimate for p.=0.5614

ANSWER0.5614

99% confidence interval for population proportion is

p^-zsqrt(p^(1-p)/n,p^+zsqrt(p^(1-p)/n

0.5614-2.576*sqrt(0.5614*(1-0.5614)/5454,0.5614+2.576*sqrt(0.5614*(1-0.5614)/5454

0.544,0.579

lower limit=0.544

upper limit=0.579