Trout were sampled from two different lake populations and their lengths measured. The researchers are interested in knowing whether the average length distribution for the trout in lake 1 (group1) are greater than the average length distribution for the trout in lake 2 (group 2). Using R and the Wilcoxon Rank Sum-test answer the following questions for the data available:
Lake1 | Lake2 |
21.85 | 42.6 |
31.4 | 32.65 |
78.5 | 28.3 |
11.7 | 19.7 |
41.15 | 29.45 |
27.55 | 16.05 |
25.4 | 24.15 |
35.8 | 14.3 |
8.05 | 39.65 |
38.35 | 24.65 |
27.7 | 34.95 |
26.3 | 27.45 |
31.25 | 28.15 |
57.35 | 32.25 |
33.15 | 69.75 |
27.85 | 32.2 |
39.25 | 30.35 |
36.65 | 45.4 |
44.4 | 34.3 |
35.85 | 28.1 |
31.6 | 31.65 |
14.4 | 11.35 |
19.85 | 41.2 |
31.75 | 51.65 |
28.05 | 30.6 |
32.1 | 21 |
33.6 | 31.95 |
43.3 | 57.75 |
24.05 | 35.85 |
29.7 | 20 |
14.4 | 20.25 |
26.35 | |
32.1 | |
40.5 | |
30.05 | |
24.95 | |
32.5 | |
28.3 | |
27.7 | |
53.65 |
Calculate the value of the test statistic W
The test has been coded been in R.
The Code of R is given below:
>
lake1<-c(21.85,31.4,78.5,11.7,41.15,27.55,25.4,35.8,8.05,38.35,27.7,26.3,31.25,57.35,33.15,27.85,39.25,36.65,44.4,35.85,31.6,14.4,19.85,31.75,28.05,32.1,33.6,43.3,24.05,29.7,14.4,26.35,32.1,40.5,30.05,24.95,32.5,28.3,27.7,53.65)
>
lake2<-c(42.6,32.65,28.3,19.7,29.45,16.05,24.15,14.3,39.65,24.65,34.95,27.45,28.15,32.25,69.75,32.2,30.35,45.4,34.3,28.1,31.65,11.35,41.2,51.65,30.6,21,31.95,57.75,35.85,20,20.25)
> wilcox.test(lake1,lake2,alternative = "greater")
Wilcoxon rank sum test with continuity correction
data: lake1 and lake2
W = 624, p-value = 0.4838
alternative hypothesis: true location shift is greater than 0
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