Question

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below.

Morgan got a score of 77.1; this version has a mean of 68.7 and a standard deviation of 12.

Alissa got a score of 264.6; this version has a mean of 225 and a standard deviation of 18.

Kerri got a score of 7.36; this version has a mean of 6.6 and a standard deviation of 0.4.

If the company has only one position to fill and prefers to fill it with the applicant who performed best on the aptitude test, which of the applicants should be offered the job?

Answer 1

1) In case of Morgan

Mean ( μ ) = 68.7 and

standard deviation (σ) = 12

Morgan's score (x ) = 77.1

z = (x - μ ) ÷ σ

z = (77.1- 68.7) ÷ 12

z = 0.7

Using z table, area to the left of z= 0.7 is 0.7580

Therefore Morgan got 75.80% in his test.

2) In case of Alissa

Mean ( μ ) =225

Standard deviation ( σ ) =18

Alissa's score ( x) = 264.6

z =( x- μ) ÷ σ

z = ( 264.6 - 225) ÷ 18

z = 2.2

Using z table, area to the left of z = 2.2 is 0.9861

Therefore Alissa got 98.61% in her test.

3) In case of Kerri,

Mean ( μ) = 6.6 and

Standard deviation ( σ ) = 0.4

Kerri's score (x) = 7.36

z = ( x - μ ) ÷ σ

z = ( 7.36 - 6.6 ) ÷ 0.4

z= 1.9

Using z table, area to the left of z= 1.9 is 0.9713

Therefore Kerri got 97.13% in the test.

Therefore the performance of Alissa is best.

Therefore Alissa should be offered the job.