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Assume that I don't have IQ scores that are normally distributed with a mean of 105...


Assume that I don't have IQ scores that are normally distributed with a mean of 105 in a standard deviation of 15 find the probability that a randomly selected adult has an IQ between 95 and 115

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Answer #1

Answer: Assume that I don't have IQ scores that are normally distributed with a mean of 105 in a standard deviation of 15.

find the probability that a randomly selected adult has an IQ between 95 and 115.

Solution:

Mean, μ = 105

Standard deviation, σ = 15

P(95 < X < 115) = P(95 - 105 /15 < Z < 115 - 105 / 15)

P(95 < X < 115) = P(- 0.67 < Z < 0.67)

P(95 < X < 115) = P(Z < 0.67) - P(Z < - 0.67)

P(95 < X < 115) = 0.7486 - 0.2514 (from z table)

P(95 < X < 115) = 0.4972

Therefore, the probability that a randomly selected adult has an IQ between 95 and 115 is 0.4972.

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