Result:
ESPN reports that the average income of an NFL players 1.5 million for the population standard deviation of 200,000 if they randomly select 500 players and determine their average income of the sample of 1,458,000. which one is the test statistic
= -4.6957
Z Test of Hypothesis for the Mean |
|
Data |
|
Null Hypothesis m= |
1500000 |
Level of Significance |
0.05 |
Population Standard Deviation |
200000 |
Sample Size |
500 |
Sample Mean |
1458000 |
Intermediate Calculations |
|
Standard Error of the Mean |
8944.2719 |
Z Test Statistic |
-4.6957 |
Two-Tail Test |
|
Lower Critical Value |
-1.9600 |
Upper Critical Value |
1.9600 |
p-Value |
0.0000 |
Reject the null hypothesis |
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