Question

A poll asked people in the U.S. whether they were satisfied with their financial situation. Out...

A poll asked people in the U.S. whether they were satisfied with their financial situation. Out of 2038 people, 478 reported that they were satisfied. Two years later, the second poll was taken asking the same question. The second poll found 537 out of 1976 people were satisfied.

(a) Construct a 95% confidence interval for the change in proportion of people satisfied in their financial situation over the two years.

(b) A sociologist claims the proportion increased by more than 0.05 over the two years. Does your confidence interval support this claim?

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

To calculate the 95% confidence interval we use the critical value of z.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Satisfied? A 2010 poll asked people of a certain region whether they were satisfied with their...
Satisfied? A 2010 poll asked people of a certain region whether they were satisfied with their financial situation. A total of 342 out of 831 people said they were satisfied. The same question was asked in 2012, and 304 out of 1162 people said they were satisfied. Part: 0 / 20 of 2 Parts Complete Part 1 of 2 (a) Construct a 90% confidence interval for the difference between the proportions of adults who said they were satisfied in 2012...
In a poll survey 1200 people were chosen by random sampling and asked whether they supported...
In a poll survey 1200 people were chosen by random sampling and asked whether they supported a proposed amendment or not. 216 of the participants supported it. Determine the 95% confidence interval for the proportion of amendment supporters. What are the lower and upper bounds of the confidence interval?
In a survey, people were asked whether they prefer candidate A or candidate B. Out of...
In a survey, people were asked whether they prefer candidate A or candidate B. Out of 264 people, 90 said they prefer candidate A. Find the sample proportion and 95% confidence interval for this statistic. (Round all answers to 2 decimal places.) Sample proportion= Confidence Interval= to =
In a recent poll, 600 people were asked if they liked soccer, and 10% said they...
In a recent poll, 600 people were asked if they liked soccer, and 10% said they did. Based on this, construct a 90% confidence interval for the true population proportion of people who like soccer. As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 2 for a 95% confidence interval --Use z = 2.576 for a 99% confidence interval. Give your answers as decimals, to 4 decimal places. [________, ________]
In a recent poll, 300 people were asked if they liked soccer, and 37% said they...
In a recent poll, 300 people were asked if they liked soccer, and 37% said they did. Based on this, construct a 90% confidence interval for the true population proportion of people who like soccer. As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 2 for a 95% confidence interval --Use z = 2.576 for a 99% confidence interval. Give your answers as decimals, to 4 decimal places. [,]
In a recent Pew Research poll, 287 out of 522 randomly selected men in the U.S....
In a recent Pew Research poll, 287 out of 522 randomly selected men in the U.S. were able to identify Egypt when it was highlighted on a map of the Middle East. When 520 randomly selected women were asked, 233 were able to do so. Construct a 95% confidence interval for the difference in the proportion of U.S. men and the proportion of U.S. women who can identify Egypt on a map.
in a random poll taken in 2008, Gallup asked 1006 national adults whether they were baseball...
in a random poll taken in 2008, Gallup asked 1006 national adults whether they were baseball fans. 433 of the sample said they were. Construct a 95% confidence interval​ to estimate the ​proportion​ of national adults who are baseball fans. ​Use 4 non-zero decimal places on calculations. a) Find the Zα/2 b) Find σpˆ c) Find the margin of error (MoE) and construct the confidence interval
A poll taken this year asked 1010 adults whether they were fans of a particular sport...
A poll taken this year asked 1010 adults whether they were fans of a particular sport and 47​% said they were. Last​ year, 46​% of a​ similar-size sample had reported being fans of the sport. Complete parts a through e below. ​a) Find the margin of error for the poll taken this year if one wants 95​% confidence in the estimate of the percentage of adults who are fans of the sport. MEequals nothing ​(Round to three decimal places as​...
In a recent poll, 500 people were asked if they liked baseball, and 57% said they...
In a recent poll, 500 people were asked if they liked baseball, and 57% said they did. Find the margin of error of this poll, at the 95% confidence level. As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 2 for a 95% confidence interval --Use z = 2.576 for a 99% confidence interval. Give your answer rounded to three decimal places.
A poll taken this year asked 1006 adults whether they were fans of a particular sport...
A poll taken this year asked 1006 adults whether they were fans of a particular sport and 39 ​% said they were. Last​ year, 44 ​% of a​ similar-size sample had reported being fans of the sport. Complete parts a through e below a) Find the margin of error for the poll taken this year if one wants 95​% confidence in the estimate of the percentage of adults who are fans of the sport. b) Explain what that margin of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT