Determine
mu Subscript x overbarμx
and
sigma Subscript x overbarσx
from the given parameters of the population and sample size.
muμequals=8686,
sigmaσequals=1818,
nequals=8181
mu Subscript x overbarμxequals=nothing
sigma Subscript x overbarσxequals=nothing
Solution :
Given that,
mean = = 8686
population standard deviation = =1818
sample size. n = 8181
= 8686
= ( /n)
= (1818 / 8181 )
= 20.1
= 20.1
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