Question

I observed whether or not passers-by in front of my house observed the 6 foot social distance requirement. I recorded a 1 if the passer-by observed the rule and a 0 if the passer-by did not observe the rule. Here is the tally for a sample of 8 passers-by.

1 1 0 0 0 0 1 0

You may treat this tally as a sample from a distribution of binary choices people make on my street.

1.Using the sample above, what is the probability that 6 or more passers-by will observe the 6 foot social distancing rule?

Select one:

a. From about 96.55 per cent

b. About 37.5 per cent

c. About 3.6 per cent

d. About 62.5 per cent

2. What are the lower and upper bounds of the 95 per cent confidence interval for this sample if we believe that the sample is drawn from a binomial distribution?

Select one:

a. From about 5 to 95 per cent of passers-by will observe the rule

b. From about 4 to 70 per cent will observe the rule

c. From about 38 to 62 per cent will observe the rule

d. From about 3 to 98 per cent will observe the rule

3. At the 5 per cent significance level, evaluate the claim that in this sample, the average proportion of compliant passers-by is no different than 50/50 (50 percent): you might as well have flipped a coin. Disregard any knowledge of a belief that this sample was drawn from the binomial distribution. [HINT: calculate the sample mean and standard deviation of the tally]

Select one:

a. Reject the claim as false and be wrong about rejecting the claim 95 per cent of the time

b. Reject the claim as false and be wrong about rejecting the claim 5 per cent of the time

c. Accept the claim as true and be wrong about accepting the claim 95 per cent of the time

d. Accept the claim as true and be wrong about accepting the claim 5 per cent of the time

Answer 1

Answer:

1)

2)

Here iam writing only part 1 & 2 only as early as possible i can write remaining one.

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