A 90% confidence interval for the proportion of coffee drinkers that add sugar and creme has results in the following output:
one sample proportion summary confidence interval:
p: proportion of success
method:standard-wald
90% confidence interval results:
proportion: p
count:1136
total:1803
sample prop: 0.63006101
std. edrr.: 0.011369948
l. limit: 0.61135911
u. limit: 0.6487629
a. Identify the values for n, p, ˆ q, ˆ and E.
b. Write a statement that interprets the 90% confidence interval
An alternative way to calculate margin of error that is E is
( l. Limit + u. Limit )/2
= ( 0.61135911 + 0.6486629 )/2
= 0.018702
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