An organization claims that 39.2% of all Americans approve of candidate A. In a random sample of 100 Americans approximate the probability that at least 35 people will approve of candidate A.
Here we have
n=100 and p=0.392
Since np = 39.2 and n(1-p) = 60.8 both are greater than 5 so we can use normal approximation here.
Using normal approximation, X has approximately normal distribution with mean and SD as follows:
The z-score for X = 35-0.5 = 34.5 is
The probability that at least 35 people will approve of candidate A is
P(X >= 35) = P(X > 34.5) = P(z > -0.96) = 1 - P(z <= -0.96) = 0.8315
Answer: 0.8315
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