Question

Suppose the number of cars in a household has a binomial distribution
with parameters n = 20, and p = 10 %.
Find the probability of a household having:
(a) 7 or 9 cars
(b) 10 or more cars
(c) more than 7 cars

Answer 1

Let X denote the number of cars in a household. Then X~Binomial(n=20,p=0.1)

a)

Required probability =

b)

Required probability =

{Using Probability tables}

c)

Required probability =

{Using Probability tables}