A box has 8 red, 5 yellow, and 7 green balls. If three balls are drawn at random with replacement, the probability that two balls are yellow or green is
There are 5+7=12 yellow or green balls out of a total of 8+5+7=20 balls.
the probability of drawing a yellow or green ball from a total of 20 balls is
A total of 3 balls are drawn. Let X be the number of yellow or green balls present in 3 balls drawn. Since each ball is drawn at random, with replacement, the probability drawing a yellow or green ball remains the same at 0.60 for each of the 3 draws.
X has a Binomial distribution with parameters, number of trials, n=3 and success probability, p=0.60.
The probability of drawing X=x yellow or green balls is
The probability of drawing X=2 yellow or green balls is
ans: the probability that two balls are yellow or green is 0.432
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