A random sample of 20 seniors from a large school district had a mean Math SAT score of 450 and a sample standard deviation of 85. Suppose we wanted to plan a similar study with just female seniors. We want to have a margin of error of 25 with 95% confidence. What is the sample size needed to achieve this margin of error? Assume that the standard deviation s = 100.
Solution :
Given that,
Population standard deviation = = 100
Margin of error = E = 25
At 95% confidence level the z is,
= 1 - 95%
= 1 - 0.95 = 0.05
/2 = 0.025
Z/2 = Z0.025 = 1.96
sample size = n = [Z/2* / E] 2
n = [1.96 *100 / 25]2
n = 61.46
Sample size = n = 62
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