Home vs Road Wins – Significance Test: For the NHL regular season, the Chicago Blackhawks won 26 out of 41 home games and won 18 out of 41 away games. Clearly the Blackhawks won a greater proportion of home games. Here we investigate whether or not they did significantly better at home than on the road. The table summarizes the relevant data. The p̂'s are actually population proportions but you should treat them as sample proportions. The standard error (SE) is given to save calculation time if you are not using software.
Data Summary
number of | total number | Proportion of | |
Game Type | wins (x) | of games (n) | wins (p̂) |
Home | 26 | 41 | 0.63415 |
Road | 18 | 41 | 0.43902 |
SE = 0.11014
The Test: Test the claim that the proportion of wins at home was significantly greater than on the road. Use a 0.05 significance level.
(a) Letting p̂1 be the proportion of wins at home and p̂2 be the proportion of wins on the road, calculate the test statistic using software or the formula
z =
(p̂1 − p̂2) − δp |
SE |
where δp is the hypothesized
difference in proportions from the null hypothesis and the standard
error (SE) given with the data. Round your answer
to 2 decimal places.
z =
To account for hand calculations -vs- software, your answer
must be within 0.01 of the true answer.
(b) Use software or the z-table to get the P-value of the test
statistic. Round to 4 decimal places.
P-value =
(c) What is the conclusion regarding the null hypothesis?
reject H0
fail to reject H0
(d) Choose the appropriate concluding statement.
The data supports the claim that the proportion of wins at home was significantly greater than on the road.
While the proportion of wins at home was greater than on the road, the difference was not great enough to be considered significant.
We have proven that the Blackhawks always do better at home games.
We have proven there was no difference in the proportion of wins at home than wins on the road.
(a)
H0: Null Hypothesis: p1 p2 ( the proportion of wins at home was not significantly greater than on the road. )
HA:Alternative Hypothesis: p1 > p2 ( the proportion of wins at home was significantly greater than on the road. ) (Claim)
n1 = 41
1 =26/41 = 0.63415
n2 = 41
2 = 15/41 = 0.43902
Pooled Proportion is given by:
Test Statistic is given by:
Z = 1.77
(b)
By Technology, Cumulative Area Under Standard Normal Curve = 0.9618
p value = 1 - 0.9618 = 0.0382
p value = 0.0382
(c)
Correct option:
reject H0
(d)
Correct option:
The data supports the claim that the proportion of wins at home was significantly greater than on the road.
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