Question

There is a study that shows that young adults watch a MEAN.P of 6.50 hours of youtube.com
videos each day with a STDEV.P of 2.50 hours.
Suppose a sample of 36 young adults were chosen, what is the probability (percentage)
that these students watch between 5.50 hours and 5.75 hours of youtube.com videos each day?

Answer 1

Solution :

= / n = 2.50 / 36 = 0.4167

= P[(5.50 - 6.50) / 0.4167 < ( - ) / < (5.75 - 6.50) / 0.4167)]

= P(-2.40 < Z < -1.80)

= P(Z < -1.80) - P(Z < -2.40)

= 0.0359 - 0.0082

= 0.0277

Probability = 0.0277