In a given university, number of credits completed by a BS graduate is a normal distribution. The average credits was 128.8, with a standard deviation of 3.2.
X denotes number of credits completed by a BS graduate
P(125<X<134)=0.8304035
proportion of graduates will finish between 125 and 134 credits=0.83(Approximate).
We are to find 'x' credits such that P(X>x)=.015.
Here x=135.7443
Y denotes number of students earned less than 138 credits.
P(Y=4)=1.33328e-14
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