The annual per capita consumption of fresh bananas (in pounds) in the United States can be approximiated by the normal distribution, with a mean of 8.9 pounds and a standard deviation of 2 pounds. Answer the following questions about the specified normal distribution. (a) What is the smallest annual per capita consumption of bananas that can be in the top 10% of consumptions? (b) What is the largest annual per capita consumption of bananas that can be in the bottom 5% of consumption? Click to view page 1 of the Standard Normal Table. LOADING... Click to view page 2 of the Standard Normal Table. LOADING... (a) The smallest annual per captita consumption of bananas that can be in the top 10% of consumptions is nothing pounds. (Round to one decimal place as needed.) (b) The largest annual per capita consumption of bananas that can be in the bottom 5% of consumptions is nothing pounds. (Round to one decimal place as needed.)
Solution :
mean = = 8.9
standard deviation = = 2
Using standard normal table,
P(Z > z) = 10%
1 - P(Z < z) = 0.10
P(Z < z) = 1 - 0.10 = 0.90
P(Z < 1.28) = 0.90
z = 1.28
Using z-score formula,
x = z * +
x = 1.28 * 2 + 8.9 = 11.5
smallest annual per captita = 11.5 pounds
(b)
P(Z < z) = 5% = 0.05
P(Z < -1.645) = 0.05
z = -1.645
Using z-score formula,
x = z * +
x = -1.645 * 2 + 8.9 = 5.6
largest annual per captita = 5.6 pounds
Get Answers For Free
Most questions answered within 1 hours.