Question

In a survey of women in a certain country​ (ages 20minus−​29), the mean height was 65.6...

In a survey of women in a certain country​ (ages

20minus−​29),

the mean height was

65.6

inches with a standard deviation of

2.81

inches. Answer the following questions about the specified normal distribution.​(a) What height represents the

95th

​percentile?

​(b) What height represents the first​ quartile?

Click to view page 1 of the table.

LOADING...

Click to view page 2 of the table.

LOADING...

​(a) The height that represents the

95th

percentile is

nothing

inches.

​(Round to two decimal places as​ needed.)

​(b) The height that represents the first quartile is

nothing

inches.

​(Round to two decimal places as​ needed.)

Homework Answers

Answer #1

Solution :

mean = = 65.6

standard deviation = = 2.81

Using standard normal table,

(a)

P(Z < z) = 95%

P(Z < 1.645) = 0.95

z = 1.645

Using z-score formula,

x = z * +

x = 1.645 * 2.81 + 65.6 = 70.22

95th percentile = 70.22

(b)

P(Z < z) = 25%

P(Z < -0.67) = 0.25

z = -0.67

Using z-score formula,

x = z * +

x = -0.67 * 2.81 + 65.6 = 63.72

First quartile = 63.72

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a survey of women in a certain country​ (ages 20minus​29), the mean height was 64.1...
In a survey of women in a certain country​ (ages 20minus​29), the mean height was 64.1 inches with a standard deviation of 2.66 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile? Click to view page 1 of the table. LOADING... Click to view page 2 of the table. LOADING... ​(a) The height that represents the 95th percentile is 68.46 68.46 inches. ​(Round to two...
In a survey of women in a certain country​ (ages 20minus−​29), the mean height was 66.6...
In a survey of women in a certain country​ (ages 20minus−​29), the mean height was 66.6 inches with a standard deviation of 2.93 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile In a survey of women in a certain country​ (ages 20minus−​29), the mean height was 66.6 inches with a standard deviation of 2.93 inches. Answer the following questions about the specified normal distribution....
In a survey of women in a certain country​ (ages 20minus​29), the mean height was 63.1...
In a survey of women in a certain country​ (ages 20minus​29), the mean height was 63.1 inches with a standard deviation of 2.85 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?
In a survey of men in a certain country​ (ages 20-29), the mean height was 64.8...
In a survey of men in a certain country​ (ages 20-29), the mean height was 64.8 inches with a standard deviation of 2.7 inches.​(a) What height represents the 90th ​percentile? ​(b) What height represents the first​ quartile? Click to view page 1 of the Standard Normal Table. LOADING... Click to view page 2 of the Standard Normal Table. LOADING... ​(a) The height that represents the 90th percentile is ? inches. ​(Round to two decimal places as​ needed.) ​(b) The height...
In a survey of women in a certain country​ (ages 20-​29), the mean height was 66.3...
In a survey of women in a certain country​ (ages 20-​29), the mean height was 66.3 inches with a standard deviation of 2.71 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? round to two decimal places as needed ​(b) What height represents the first​ quartile? round to two decimal places as needed
In a survey of men in a certain country​ (ages 20minus−​29), the mean height was 62.862.8...
In a survey of men in a certain country​ (ages 20minus−​29), the mean height was 62.862.8 inches with a standard deviation of 2.72.7 inches. ​(a) What height represents the 9898th ​percentile? ​(b) What height represents the first​ quartile? Round to two decimal places as needed
In a survey of women in a certain country​ (ages 20−​29) the mean height was 64.2...
In a survey of women in a certain country​ (ages 20−​29) the mean height was 64.2 inches with a standard deviation of 2.93 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?
In a survey of women in a certain country​ (ages 20−​29), the mean height was 66.9...
In a survey of women in a certain country​ (ages 20−​29), the mean height was 66.9 inches with a standard deviation of 2.84 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?
In a survey of women in a certain country​ (ages 20-29), the mean height was 65.4...
In a survey of women in a certain country​ (ages 20-29), the mean height was 65.4 inches with a standard deviation of 2.66 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?
In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.1...
In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.1 inches with a standard deviation of 2.91 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?