The waiting times (in minutes) of a random sample of 22 people at a bank have a sample standard deviation of 4.2 minutes. Construct a confidence interval for the population variance sigma squaredσ2 and the population standard deviation sigmaσ. Use a 90% level of confidence. Assume the sample is from a normally distributed population.
Let's write the given information
n = sample size = 22
s = sample standard deviation = 4.2
Let's use minitab:
Step 1) Click on Stat>>>Basic Statistics >>1 variance...
Data : Select "sample standard deviation"
Sample size: 22
Sample standard deviation: 4.2
Step 2) Click on Option
Confidence level = 90
Alternative: Not equal
Then click on OK
Again Click on OK
So we get the following output:
From the above output the 90% Confidence Interval for population variance is = (11.3, 32.0)
And the 90% Confidence Interval for population standard deviation is = (3.37, 5.65)
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