Question

Q30. YouTube would like to test the hypothesis that the average length of an online video...

Q30. YouTube would like to test the hypothesis that the average length of an online video watched by a user is more than 8 minutes. A random sample of 36 people watched online videos that averaged 8.7 minutes in length. It is believed that the population standard deviation for the length of online videos is 3 minutes.

a. The​ p-value for this hypothesis test would be​ _______.

A.

0.9192

B.

0.5910

C.

0.0808

D.

0.4090

b. If YouTube uses an

alphaαequals=0.05

in hypothesis​ tests, the conclusion​ is:

A.

Fail to Reject the Null hypothesis

B.

Reject the Null hypothesis

c. If YouTube uses an

alphaαequals=0.10

in hypothesis​ tests, the conclusion​ is:

A.

Reject the Null hypothesis

B.

Fail to Reject the Null hypothesis

Q31.

During the

2007dash–2008

decline in the housing​ market, it appeared that the average size of a newly constructed house fell. To investigate this​ trend, the square footages of a random sample of houses built in 2008 were compared to houses built in 2018.

a. Perform a hypothesis test to determine if the average home constructed in 2008 was larger than a home built in 2018. Let the 2008 houses be designated as Population 1 and the 2018 houses be designated as Population 2.

Identify the null and alternative hypotheses. Choose the correct answer below.

A.

Upper H 0H0​:mu 1μ1minus−mu 2μ2less than or equals≤0

Upper H 1H1​:mu 1μ1minus−mu 2μ2greater than>0

B.

Upper H 0H0​:mu 1μ1minus−mu 2μ2greater than or equals≥0

Upper H 1H1​:mu 1μ1minus−mu 2μ2less than<0

C.

Upper H 0H0​:mu 1μ1minus−mu 2μ2not equals≠0

Upper H 1H1​:mu 1μ1minus−mu 2μ2equals=0

D.

Upper H 0H0​:mu 1μ1minus−mu 2μ2equals=0

Upper H 1H1​:mu 1μ1minus−mu 2μ2not equals≠0

b. Is this comparison of two samples of houses​ (2008 and​ 2018) dealing with 2 independent samples or dependent​ matched-pair samples? Choose the correct answer.

A.

Independent samples

B.

Dependent​ Matched-Pair samples

Homework Answers

Answer #1

Q30)

H0: <= 8

Ha: > 8

Test statistics

z = ( - ) / ( / sqrt(n) )

= ( 8.7 - 8) / ( 3 / sqrt(36) )

= 1.4

p-value = P(Z > z)

= P(Z > 1.4)

= 0.0808

If = 0.05

Since p-value > 0.05 , Fail to reject the null hypothesis

If = 0.10

Since p-value < 0.10 , reject the null hypothesis

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
YouTube would like to test the hypothesis that the average length of an online video watched...
YouTube would like to test the hypothesis that the average length of an online video watched by a user is more than 8 minutes. A random sample of 37 people watched online videos that averaged 8.7 minutes in length it is believed that the populations standard deviation for the length of online videos is 2.5 minutes. YouTube would like to set a=.02 the critical value for this hypothesis test would be...
YouTube would like to test the hypothesis that the average length of an online video watched...
YouTube would like to test the hypothesis that the average length of an online video watched by a user is more than 8 minutes. A random sample of 37 people watched online videos that averaged 8.7 minutes in length. It is believed that the population standard deviation for the length of online videos is 2.5 minutes. YouTube would like to set ΅ = 0.02. The p-value for this hypothesis test would be ________. A) 0.0150 B) 0.0245 C) 0.0446 D)...
1a. YouTube would like to test the hypothesis that the average length of an online video...
1a. YouTube would like to test the hypothesis that the average length of an online video watched by a user is less than six minutes. A random sample of 40 people watch online videos that average 5.4 minutes in line. It is believed that the sample standard deviation for the length of online videos is 1.7 minutes. YouTube would like to set the level of significance equal to 0.05. The correct hypothesis statement for this hypothesis test would be 1b....
According to​ research, holiday shoppers spent an average of ​$372 over a holiday weekend in 2008....
According to​ research, holiday shoppers spent an average of ​$372 over a holiday weekend in 2008. The accompanying data show the amount spent by a random sample of holiday shoppers during the same weekend in 2009. Complete parts a and b below. data table: ​$429 ​$271 ​$375 ​$235 ​$225 ​$214 ​$356 ​$433 ​$385 ​$396 ​$316 ​$66 ​$414 ​$431 ​$381 ​$284 a. Retailers were concerned that the recent economic downturn was going to affect holiday sales. Does this sample support these...
According to a​ survey, people in a certain country ate an average of 205 meals in...
According to a​ survey, people in a certain country ate an average of 205 meals in restaurants in 2001. The data in the accompanying table show the number of meals eaten in restaurants as determined from a random sample of people in this country in 2009. Complete parts​ (a) through​ (d) below. LOADING... Click the icon to view the data table. 213 132 199 344 141 80 183 309 56 197 168 310 95 231 266 292 226 316 206...
Suppose the average size of a new house built in a certain county in 2006 was...
Suppose the average size of a new house built in a certain county in 2006 was 2,271 square feet. A random sample of 30 new homes built in this county was selected in 2010. The average square footage was 2,187​, with a sample standard deviation of 220 square feet. a. Using alphaαequals=0.10​, does this sample provide enough evidence to conclude that the average house size of a new home in the county has changed since​ 2006? b. Use technology to...
Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test....
Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test. Upper H 0H0​: p equals=0.3 versus Upper H 1H1​: p greater than>0.3 n equals=125​; x equals=43​; alphaαequals=0.1
Hi, having an issue mostly with the P value and the last multiple choice question. But,...
Hi, having an issue mostly with the P value and the last multiple choice question. But, would like to see your choices. Thank you! Direction of Travel Departure Arrival Mean speed ​(feet per​ minute) 252 266 Standard deviation​(feet per​ minute) 52 34 Sample size 35 35 Do people walk faster in the airport when they are departing​ (getting on a​ plane) or do they walk faster when they are arriving​ (getting off a​ plane)? A reputable researcher measured the walking...
Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test....
Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test. Upper H 0H0​: pequals=0.40.4 versus Upper H 1H1​: pgreater than>0.40.4 nequals=100100​; xequals=5050​; alphaαequals=0.05 1) Calculate the test statistic, Z0 2) Identify the P Value 3)Choose the correct result: - Do not reject the null hypothesis; b/c the p value is less than α -Do not reject the null hypothesis; b/c the p value is greater than α - Reject the null hypothesis; b/c the...
Listed below are systolic blood pressure measurements​ (mm Hg) taken from the right and left arms...
Listed below are systolic blood pressure measurements​ (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.050.05 significance level to test for a difference between the measurements from the two arms. What can be​ concluded? Right arm 152152 148148 115115 129129 136136 Left arm 172172 168168 177177 148148 149149 In this​ example,...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT