At least how many time do you have to roll a fair die to be sure that probability of rolling at least one 6 is greater than 9 in 10 (0.9)?
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Answer is 13.
Let that be n number of times.
When rolled n times, (5/6)^n is probability that 6 won't come up
1- (5/6)^n > .9
So, 1-.9 > (5/6)^n
.1 > (5/6)^n
Both sides, applying natural Log,
Ln(.1) > n*Ln (5/6)
n> 12.65 so, 13 times. ( sign of > reverses when -ive number is multiplied both the sides)
So, dice must be rolled atleast 13 times to be sure that probability of rolling at least one 6 is greater than 9 in 10 (0.9)
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