To study how social media may influence the products consumers buy, researchers collected the opening weekend box office revenue (in millions of dollars) for 23 recent movies and the social media message rate (average number of messages referring to the movie per hour). The data are available below. Conduct a complete simple linear regression analysis of the relationship between revenue (y) and message rate (x).o study how social media may influence the products consumers buy, researchers collected the opening weekend box office revenue (in millions of dollars) for 23 recent movies and the social media message rate (average number of messages referring to the movie per hour). The data are available below. Conduct a complete simple linear regression analysis of the relationship between revenue (y) and message rate (x)
Message Rate |
Revenue ($millions) |
||
---|---|---|---|
1363.2 |
146 |
||
1219.2 |
79 |
||
681.2 |
67 |
||
583.6 |
37 |
||
454.7 |
35 |
||
413.9 |
34 |
||
306.2 |
21 |
||
289.8 |
18 |
||
245.1 |
18 |
||
163.9 |
17 |
||
148.9 |
16 |
||
147.4 |
15 |
||
147.3 |
15 |
||
123.6 |
14 |
||
118.1 |
13 |
||
108.9 |
13 |
||
100.1 |
12 |
||
90.3 |
11 |
||
89.1 |
6 |
||
70.1 |
6 |
||
56.2 |
5 |
||
41.6 |
3 |
||
8.4 |
1 |
The least squares regression equation is y=(−0.031+ 0.086x).
(Round to three decimal places as needed.)
Check the usefulness of the hypothesized model. What are the hypotheses to test?
A.
H0: β1≠0 againstHa:β1=0
B.H0:β0=0 against Ha: β0 ≠0
C.H0: β≠0 against Ha:β0=0
D.H0:β1=0 against Ha:β1≠0 The answer is correct.
Determine the estimate of the standard deviation.
s=____________ (Round to two decimal places as needed.)
Following table shows the output of regression analysis generated by excel:
SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.957130968 | |||||
R Square | 0.916099691 | |||||
Adjusted R Square | 0.912104438 | |||||
Standard Error | 9.592074495 | |||||
Observations | 23 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 21097.13859 | 21097.13859 | 229.2970513 | 8.96384E-13 | |
Residual | 21 | 1932.165756 | 92.00789312 | |||
Total | 22 | 23029.30435 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | -0.03086767 | 2.644826475 | -0.011670962 | 0.990798298 | -5.531085404 | 5.469350063 |
Message Rate(x) | 0.086462093 | 0.005709874 | 15.14255762 | 8.96384E-13 | 0.07458776 | 0.098336425 |
The least square regression line is:
y' = -0.031 + 0.086x
The hypotheses are:
D.H0:β1=0 against Ha:β1≠0
The estimate of the standard deviation is
s = 9.59
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