Given two independent random samples with the following results:
n1 | = | 11 | n2 | = | 13 | |
xbar1 | = | 162 | xbar^2 | = | 130 | |
s1 | = | 31 | s2 | = | 30 |
Use this data to find the 95% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed.
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Step 1 of 3: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Step 2 of 3: Find the standard error of the sampling distribution to be used in constructing the confidence interval. Round your answer to the nearest whole number.
Step 3 of 3: Construct the 95% confidence interval. Round your answers to the nearest whole number. Both lower and upper endpoint.
The population variances are equal.
So we have to use here pooled variance.
Step1:
Degrees of freedom = n1 + n2 - 2 = 11 + 13 - 2 = 22
Level of significance = 0.05
Critical value = tc = 2.074 ( From t table)
Step 2:
Standard error is SE
Step 3:
We have to construct 95% confidence interval for the difference between means.
Formula is
E = tc*SE = 2.074*12.4781 = 25.8780
( 32 - 25.8780 , 32 + 25.8780) = > ( 6.1220 , 57.8780) = > ( 6 , 58)
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