Noise levels at 6 airports were measured in decibels yielding the following data:
157,164,160,147,152,153
Construct the 99% confidence interval for the mean noise level at such locations. Assume the population is approximately normal.
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Step 4 of 4 :
Construct the 99% confidence interval. Round your answer to one decimal place.
From the given data
= 155.5 , S = 6.091
t critical value at 0.01 level with 5 df = 4.032
99% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
155.5 - 4.032 * 6.091 / sqrt(6) < < 155.5 + 4.032 * 6.091 / sqrt(6)
145.5 < < 165.5
99% CI is ( 145.5 , 165.5)
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