Please use excel and explain clearly
An automobile rental agency has the following mileages for a
simple random sample of 20 cars that were rented last year:
55, 35, 65, 64, 69, 37, 88, 80, 39, 61, 54, 50, 74, 92, 59, 50, 38,
59, 29, 60.
Construct and interpret the 99% confidence interval for the
population mean.
We are 99 % confident that the population mean lies between 46.779 < μ < 69.021
Confidence Interval Estimate for the Mean: T-Statistic | |||||
Small Sample or Sigma Not Known | |||||
Data | |||||
Sample Standard Deviation | 17.384 | =STDEV.S() | |||
Sample Mean | 57.900 | =AVERAGE () | |||
Sample Size n | 20 | =COUNT() | |||
Confidence Level % | 99% | ||||
Alpha α | 0.010 | =1-B7 | |||
Degrees of Freedom | 19.000 | =B6-1 | |||
tc Value | 2.861 | =T.INV.2T(B8, B9) | |||
Standard Error of the Mean | 3.887 | =B4/SQRT(B6) | |||
Margin of Error E | 11.121 | =B10*B11 | |||
Confidence Interval | |||||
Interval Lower Limit | 46.779 | =B5-B12 | |||
Interval Upper Limit | 69.021 | =B5+B12 | |||
46.779 < μ < 69.021 |
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