Find the margin of error for the given values of c, s, and n.
cequals=0.8080,
sequals=66,
nequals=2626
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The margin of error is?
(Round to one decimal place as needed.)
To find the margin of error for given, confidence (c) = 0.80 , sample size (n) = 26 and standard deviation (s) = 6
We know that, margin of error is calculated as,
where t* is the value from t distribution with (n-1) degrees of freedom and level of significance,
Thus,
Therefore, margin of error is 1.5489
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