Question

P(X≥3) n=6 p=0.1

Answer 1

Solution :

Given that ,

p = 0.1

1 - p = 1 -0.1 = 0.9  

^{n = 6}

^{p (  x 3 )  =p (x = 3 )+ p (x = 4) + p (x = 5) +  p (x = 6 )}  

  = (6 !/ (3 - 4)!) * 0.1³ * 0.9)^{4 +}

  = (6 ! / (4 - 3)!) ^{* 0.14 * 0.9)3 +}

  ⁼ (6 ! / (5 - 2)!) * 0.15⁵* 0.85)^{2 +}

  ⁼ (6! / ( 6 - 1)!) * 0.15⁶* 0.85^{)1 +}

= 0.01585

p (  x 3 )  = 0.01585

Probability = 0.0159