All cars can be classified into one of four groups: the subcompact, the compact, themidsize, and the fullsize. There are five cars in each group. Head injury data (in hic) for the dummies in the driver's seat are listed below. Use a 0.05 significance level. Find the Pvalue to test the null hypothesis that the different weight categories have the same mean. Do the sample data suggest that larger cars are safer?
Subcompact:
681
428
917
898
520
Compact:
643
655
442
514
525
Midsize:
469
627
525
454
259
Fullsize:
384
656
502
687
360
Find the Pvalue.
(Round to three decimal places as needed.)
For given problem we use ANOVA for single factor in MSExcel.We get output as follow
Anova: Single Factor  
SUMMARY  
Groups  Count  Sum  Average  Variance  
Subcompact:  5  3444  688.8  48102.7  
Compact:  5  2779  555.8  8272.7  
Midsize:  5  2334  466.8  18100.2  
Fullsize:  5  2589  517.8  22695.2  
ANOVA  
Source of Variation  SS  df  MS  F  Pvalue  F crit 
Between Groups  135225  3  45075  1.855496  0.177853  3.238872 
Within Groups  388683.2  16  24292.7  
Total  523908.2  19 
So from the above output
p value = 0.177853
= 0.178

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