All cars can be classified into one of four groups: the subcompact, the compact, themidsize, and the full-size. There are five cars in each group. Head injury data (in hic) for the dummies in the driver's seat are listed below. Use a 0.05 significance level. Find the P-value to test the null hypothesis that the different weight categories have the same mean. Do the sample data suggest that larger cars are safer?
Subcompact:
681
428
917
898
520
Compact:
643
655
442
514
525
Midsize:
469
627
525
454
259
Full-size:
384
656
502
687
360
Find the P-value.
(Round to three decimal places as needed.)
For given problem we use ANOVA for single factor in MS-Excel.We get output as follow
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Subcompact: | 5 | 3444 | 688.8 | 48102.7 | ||
Compact: | 5 | 2779 | 555.8 | 8272.7 | ||
Midsize: | 5 | 2334 | 466.8 | 18100.2 | ||
Full-size: | 5 | 2589 | 517.8 | 22695.2 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 135225 | 3 | 45075 | 1.855496 | 0.177853 | 3.238872 |
Within Groups | 388683.2 | 16 | 24292.7 | |||
Total | 523908.2 | 19 |
So from the above output
p value = 0.177853
= 0.178
|
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